Question

box of mass 1kg is lying on a rough horizontal floor.A horizontal force starts acting on box and its magnitude changes with time as F 3t^2N where t is time in seconds. coefficient of static and kinetic friction between the box and horizontal floor are us=0.5 uk0.2. take g=10m.s^2​

Answer 1

Given:

Mass of the box = 1kg

$F_{s}$ = 3N

$F_{k}$ = 2N

To Find:

velocity

Solution:

ma = (t² - 3)

dv/dt = (3t² - 2)

Now, velocity = x/t

                      = 3(3³)/3-1/3-2(3-1)

                      = 27 - 1-4

                      = 22m/s

Therefore the velocity = 22m/s.