Box of mass m is initially at rest on a horizontal surface. A constant horizontal force of mg/2 is applied to the box directed to the right. The coefficient of friction of the surface changes with the distance pushed as μ=μ0xμ=μ0x where x is the distance from the initial location. For what distance is the box pushed until it comes to rest again ?
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By formula Work done by all forces = change in Kinetic Energy
∆KE=0
so 0= Mg/2-u°xmg
1/2-u°x=0
1/2=u°x
x=1/(2u°)
∆KE=0
so 0= Mg/2-u°xmg
1/2-u°x=0
1/2=u°x
x=1/(2u°)
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