Math, asked by krishharshu1981, 11 months ago

Box There are two cross roads at right angles, each of width 2 m, that run
parallel to the sides of rectangular plot of sides 220 m and 160 m. Find the
area of the roads.
hinnale in wie -
DO -Am and​

Answers

Answered by TheEntity
0

Step-by-step explanation:

Since, the cross-roads are at right angles. Therefore, the shape of the cross-roads must be rectangular.

Length of 1st cross-road = 220 m ( Since, it is parallel to side of 220 m of the rectangular plot)

Breadth of 1st cross-road = 2m (given)

Therefore, Area of 1st cross-road = length × breadth

= 220m × 2m

= 440 m^2

Similarly, Length of 2nd cross-road = 160 m ( Since, it is parallel to side of 160 m of the rectangular plot)

Breadth of 2m cross-road = 2m (given)

Therefore, Area of 2nd cross-road = length × breadth

= 160m × 2m

= 320 m^2

The roads intersect each other at 90°. Therefore, they must have an area in common.

Area in common = 2m × 2m

= 4m^2

Area of the roads = (Area of 1st cross-road + Area of 2nd cross-road - Area in common)

= (440 + 320 - 4) m^2

= (760-4) m^2

= 756 m^2

Therefore, Total area of roads = 756m^2.

Hope it helps :)

And, extremely sorry for the delay..

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