Math, asked by tanish212233, 5 months ago


\boxed{ \boxed{ \pink{ \underbrace{ \huge{ \bf{QUESTION}}}}}}
QUESTION






The Equation →


\begin{gathered} \bold{ \sf{ \frac{ {24x}^{2} + 25x - 47 }{ax - 2} = - 8x - 3 - \frac{53}{ax - 2}}} \\ \\ \: is \: \: true \: for \: all \: values \: of \: x ≠\frac{2}{a} ,where \: a \: \: is \: constant \: \end{gathered}
ax−2
24x
2
+25x−47

=−8x−3−
ax−2
53


istrueforallvaluesofx

=
a
2

,whereaisconstant





What is the value of a?

A) -16

B) -3

C) 3

D) 16
​​

Answers

Answered by Anonymous
2

Answer:

Please ask your question properly..

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