\boxed{ \boxed{ \pink{ \underbrace{ \huge{ \bf{QUESTION}}}}}}
QUESTION
The Equation →
\begin{gathered} \bold{ \sf{ \frac{ {24x}^{2} + 25x - 47 }{ax - 2} = - 8x - 3 - \frac{53}{ax - 2}}} \\ \\ \: is \: \: true \: for \: all \: values \: of \: x ≠\frac{2}{a} ,where \: a \: \: is \: constant \: \end{gathered}
ax−2
24x
2
+25x−47
=−8x−3−
ax−2
53
istrueforallvaluesofx
=
a
2
,whereaisconstant
What is the value of a?
A) -16
B) -3
C) 3
D) 16
Answers
Answered by
2
Answer:
Please ask your question properly..
Similar questions