Question

boy moves along the edges of a square park of side 40 m and stops at the diagonal opposite end of a point is velocity if it takes 0.5 minutes to reach

Answer 1

Correct Question:

A boy moves along the edge of a square park of side 40m and stops at the diagonally opposite end of it . Find his velocity if he takes 0.5 minutes to reach there.

Given:

• A boy moving along the edge of square park of side 40m
• Boy takes 0.5 min to reach at diagonally opposite end

To Find:

• Velocity of the boy

Diagram:

See in attachment

Solution:

We know that,

↠ Length of diagonal of square= √(2)a

where,

a is the length of the edge of square

↠ $\bf{Velocity=\dfrac{Total\:Displacement}{Total\:Time\:Taken}}$

Here,

$\sf{Displacement\:of\:boy=Length\:of\:diagonal\:of\:square\:park}$

$\sf{Displacement\:of\:boy=\sqrt{2}\times40}$

$\sf{Displacement\:of\:boy=40\sqrt{2}m}$

Also,

Time taken by boy= 0.5 min

Time taken by boy= (0.5×60)s

Time taken by boy= 30s

Now,

$\sf{Velocity\:of\:boy=\dfrac{Total\:Displacement}{Total\:Time\:Taken}}$

$\sf{Velocity\:of\:boy=\dfrac{40\sqrt{2}}{30}}$

$\sf{Velocity\:of\:boy=\dfrac{4\sqrt{2}}{3}m/s}$

$\sf{Velocity\:of\:boy=1.88m/s}$

Hence, the velocity of boy is 1.88 m/s.

Answer 2

Answer:

the answer is 1.885 m/s