Question

boy of mass M is standing on a wooden plank of mass m on a smooth horizontal floor. The boy jumps toward right with a horizontal velocity v. The magnitude of velocity of plank just after the jump is
Choose answer:

Mmv

m/M * v

M/m * v



0
answer it correct and get it the brainliest

Answer 1

$\bold{\huge{\bf{ANSWER}}}$

$\bold{\huge{\bf{Given}}}$

1) The Mass of the Boy standing on a wooden plank of mass m on a smooth horizontal floor = M

2) The boy jumps toward right with a horizontal velocity = v

$\bold{\huge{\bf{Solution}}}$

Magnitude = Force × Displacement × Cos(∅)

= Force × Displacement × Cos(90°)

= Force × Displacement × 0

= 0

$\bold{\huge{\bf{Then}}}$

The magnitude of velocity of plank just after the jump is = 0

Answer 2

Answer:

The Correct answer is Option D

Step-by-step explanation:

1) The Mass of the Boy standing on a wooden plank of mass m on a smooth horizontal floor = M

2) The boy jumps toward right with a horizontal velocity = v

Magnitude = Force × Displacement × Cos(∅)

= Force × Displacement × Cos(90°)

= Force × Displacement × 0

= 0

The magnitude of velocity of plank just after the jump is = 0

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