boy off mass 2 kg makes an elastic collision with another boy rest and continues to move in lawrenceville direction with the speed equal to 1/3 of its original speed. find mass
of the second body
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Explanation:
Let mass of second body be m kg and its velocity after collision be v.
The collision is elastic i.e e=1
∴
u−0
3
u
−v
=−1 ⟹v=
3
4u
Applying conservation of momentum:
m
1
u+0=m
1
3
u
+mv
2u=2×
3
u
+m×
3
4u
⟹m=1 kg
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