Question

boys Ravi John asif stand in a straight line is shown in the figure Ravi and Asin firecrackers at the same instant of time John hears the first sound after 2 second and the second sound after 2.5 second determine the distance between Ravi and asif the velocity of the sound in air is 330 M per second.........
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Answer 1

Answer:as the figure is not shown here let's assume Ravi(R) John(J) and Asif(A) are standing like this:

R. J. A

Therefore the answer is 1485metres

Explanation:

Ravi to John:

v =330m/s

t=2s

Therefore: s=v*t = 330*2=660 m

Asif to John :

v= 330m/s

t=2.5 s

Therefore: s = v*t = 330*2.5= 825m

Therefore distance between Asif and Ravi = 825 + 660 = 1485metres

Answer 2

Answer:

1485 meters the answer according to me