BQ bisects angle CBP. Find angle ABQ and reflex angle QBP
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as BQ bisects angle PBC, so
angle PBQ = angle QBC = angle x
now we know, sum of angles on a straight line equals 180°
therefore, x + x + 64 = 180
2x = 116
x = 58°
so, ABQ = 64 + 58 = 122°
AND QBP = 58°
angle PBQ = angle QBC = angle x
now we know, sum of angles on a straight line equals 180°
therefore, x + x + 64 = 180
2x = 116
x = 58°
so, ABQ = 64 + 58 = 122°
AND QBP = 58°
285000:
reflex of QBP is asked
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