Question

Bq)
(ii) 27a313 - 18a-b3 + 7503b2
(ii) 39(x2 + y2) + 6b(x2 + y2)
35/2​

Answer 1

Answer:

Let p, be the first term l.e; 18

And, d, be the common difference,

From given series

4th term = p+3d -3

18+ 3d = -3

Hence, d= -7

So, a = p+d = 18 – 7 = 11

And, b=p+ 2d=18 - 14 = 4

Therefore,

a+b= 11+4=15