Question

bracket 1 upon 2 into 3 upon 4 + 1 upon 2 into minus 5 upon 12 bracket close is equal to

Answer 1

Answer:

$The \: value \: of \\\big(\frac{1}{2}\times \frac{3}{4}\big)+\big(\frac{1}{2}\times \frac{-5}{12}\big)\\=\frac{1}{6}$

Step-by-step explanation:

$The \: value \: of \\\big(\frac{1}{2}\times \frac{3}{4}\big)+\big(\frac{1}{2}\times \frac{-5}{12}\big)$

$=\frac{1}{2}\big(\frac{3}{4}+\frac{(-5)}{12}\big)$

$=\frac{1}{2}\big(\frac{3}{4}-\frac{5}{12}\big)$

/* By Distributive property:

a×b+a×c=a(b+c) */

$=\frac{1}{2}\big(\frac{9-5}{12}\big)$

$=\frac{1}{2}\big(\frac{4}{12}\big)$

$=\frac{1}{2}\big(\frac{1}{3}\big)$

$=\frac{1}{6}$

Therefore,

$The \: value \: of \\\big(\frac{1}{2}\times \frac{3}{4}\big)+\big(\frac{1}{2}\times \frac{-5}{12}\big)\\=\frac{1}{6}$