Question

bracket 2 + under root minus 3(3 + under root minus 3) ​

Answer 1

Let

3+4i

=

x

+i

y

Then (

3+4i

)

2

=(

x

+i

y

)

2

⇒3+4i=x−y+2i

xy

Comparing real part and imaginary part, we get

3=x−y and 2

xy

=4⇒xy=4

∴x+y=±5 ( As x



=−5;

x

is real part )

∴x=4,y=1⇒

x

=±2,y=±1

Hence square root is ±(2+i)