bracket 3 X square + 6 y square bracket close whole power square
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(3x^2 + 6y^2)^ 2 Thus using the identity (a+b)^ 2=a^2 + 2ab + b^2 We get:- (3x^2)^2 + 2(3x^2*6y^2) + (6y^2)^2 =9x^4 + 36 x^2y^2 + 36 y^4 =9{x^4 + 4 x^2y^2 + 4 y^4} That's what I got... Hope it helps..
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(3x^2+6y^2)^2
(3x^2)^2+(6y^2)^2+2(3x^2)(6y^2)
9x^4+36y^4+36×x^2×y^2
9(x^4+4y^4+4x^2 y^2)
√(x^4+4y^4+4x^2y^2)
x^2+2y^2+2xy
(3x^2)^2+(6y^2)^2+2(3x^2)(6y^2)
9x^4+36y^4+36×x^2×y^2
9(x^4+4y^4+4x^2 y^2)
√(x^4+4y^4+4x^2y^2)
x^2+2y^2+2xy
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