Question

Brainleist question:
Calculate the molarity of pure water.

Answer 1

$\textbf{Hey there}$!!

$\textbf{Solution}$:

we know the Density of water = 1 gm $L^{-1}$

Mass of 1000 mL of water = Volume x Density

= 1000 x 1

= 1000 g

Moles of water = $\frac{Mass}{Molecular Mass}$

Mass = 1000 g

And Molecular Mass = 18

Therefore,

Moles of water = $\frac{1000}{18}$

= 55.55 mol.

Now, 55.55 moles of $H_{2}$o are
present in 1000 mL or 1L of Water.

Therefore,

Molarity = 55.55 M.

#Be Brainly.

Answer 2

${\Large{\textbf{\underline{Answer:-}}}}$

Desity of water =$\bf 1 g mL^{-1}$

$\textbf {Mass of 1000 ml of water }$

$\bf = V × d$

$\bf = 1000 mL × 1 gm^{-1 }$

$\bf = 1000 g$

$\bf Moles \:of\: water =\dfrac{1000}{8}$

$\bf = 55.55\: mol$

Now, mole of H2 O present in 1000 mL or 1 L of water. So, molarity = 55.55M