Question

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Find out point A to B

Resistance is Given each have 6ohm.​

Answer 1

Answer:

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Given:-

• Resistance of each resistor s =6 omega.

To find :-

• Equivalent resistance between A to B.

Solution :-

1. Traditional method is to solve this type of problem is to convert the network in a simplified network.
2. All the resistance are connected with point in A are all parallel

• All three cases are connected in series.
• Apply the formula of parallel connection in step 1

• $\frac{1}{r1} = \frac{1}{a} + \frac{1}{b}$
• $\frac{1}{r 1} = \frac{1}{6} + \frac{1}{6}$
• r1=3omega .

• Apply the formula of parallel connection in step 2

• $\frac{1}{r2} = \frac{1}{d } + \frac{1}{e} + \frac{1}{f}$
• r2=2omega

• Apply the formula of parallel connection in step 3
• $\frac{1}{r3} = \frac{1}{g} + \frac{1}{h} + \frac{1}{i} + \frac{1}{j}$
• $r3 = \frac{3}{2}$
• Therefore, now

• Resistance of AB= r1+r2+r3
• $rab = 3 + 2 + \frac{3}{2}$
• $rab = \frac{13}{2}$
• So, equivalent resistance of A to B is 13/2omega .

Hope it helps u mate.

Thank you.

Answer 2

Answer:

hope it helps you

refer to attachment