Question

#Brainlier of the day
If the fourth,seventh and tenth term of a GP are x,y,z respectively, prove that x,y,z are in GP.

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Answer 1

Answer:

x , y & z are in GP

Step-by-step explanation:

If the fourth,seventh and tenth term of a GP are x,y,z respectively, prove that x,y,z are in GP.

Let say GP is

a  ar  ar² ...................................... ans so on

first term = a

Common ratio = r

4th term = ar³  = x

7th term = ar⁶ = y

10th term = ar⁹ = z

for x , y , z to be in GP

y²  = xz

=> (ar⁶)² = (ar³)(ar⁹)

=> a²r¹² = a²r¹²

Hence x , y & z are in GP