Question

BRAINLIEST :


A car starts from rest and accelerates at a rate of 40 m/s2 over a time if 2.4 s. How fast is the car going at the end of this time interval? Please explain​

Answer 1

Given :-

A car starts from rest and accelerates at a rate of 40 m/s2 over a time if 2.4 s.

To Find :-

Final velocity

Solution :-

We know that

v = u + at

v = 0 + 40(2.4)

v = 40 × 24/10

v = 4 × 24

v = 96 m/s

Answer 2

Explanation:

Given:A car starts from rest and accelerates at a rate of 40 m/s2 over a time of 2.4 s.

To find: How fast is the car going at the end of this time interval? Please explain.

Solution:

Initial velocity (u)=0 m/s

because car is at rest.

Final velocity (v) = ?

acceleration (a)= 40 m/s²

time (t) = 2.4 s

The equation that contains all these terms is

$v = u + a {t} \\ \\ v = 0 + 40( {2.4)} \\ \\ v = 96 \: m {s}^{ - 1} \:$

Final answer:

Final velocity of car is 96 m/s

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