Brainliest. An object having initial velocity u is moving with acceleration a in time t find the displacement of particle in last one second (b) evaluate displacement for u =2m/s,a=1m/s,t=5s.
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Distance travelled in nth second = u +1/2a (2n-1)
Where n = second you are calculating the distance travelled in.
In this case n= last second of travel (5th)
s=2+1/2*1(2*5-1)
s=2+9/2
s=6.5m
Please mark it as brainliest.
Answered by
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Distance travelled in nth second = u +1/2a (2n-1)
Where n = second you are calculating the distance travelled in.
In this case n= last second of travel (5th)
s=2+1/2*1(2*5-1)
s=2+9/2
s=6.5m
Please mark it as brainliest.
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