Question

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from a cylinder whose height is 10 cm and diameter 14 cm, a conical
cavity of the same height and same diameter is hollowed out. The curved
surface area of cone is : ( use = and 149 - 12.2)
:) 266.4 cm sq
(b) 267.4 cm sq
(c) 268.4 cm sq
d 269.4 cm sq​

Answer 1

Answer:

659.543cm2

Step-by-step explanation:

Volume of remaining solid = volume of cylinder - volume of cone.

r=5 cm   (given)

h=12 cm

Volume of cylinder = πr2h

=3.14×52×12

=942cm2

Volume of cone = 31πr2h=31×3.14×52×12

=314cm3

Remaining volume = 942-314

=628cm3

Total surface of remaining solid = conical sutface area of cone + Area of circle + Cylindrical area of cylinder.

Conical sutface area of cone =πrr2+h2=204.203 cm2

Conical of cirle = πr2=78.54cm2

Cylindrical area of cylinder = 2πrh

=376.8cm2

Total surface area 659.543cm2

Answer By Abhishek Aade