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from a cylinder whose height is 10 cm and diameter 14 cm, a conical
cavity of the same height and same diameter is hollowed out. The curved
surface area of cone is : ( use = and 149 - 12.2)
:) 266.4 cm sq
(b) 267.4 cm sq
(c) 268.4 cm sq
d 269.4 cm sq
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Answer:
659.543cm2
Step-by-step explanation:
Volume of remaining solid = volume of cylinder - volume of cone.
r=5 cm (given)
h=12 cm
Volume of cylinder = πr2h
=3.14×52×12
=942cm2
Volume of cone = 31πr2h=31×3.14×52×12
=314cm3
Remaining volume = 942-314
=628cm3
Total surface of remaining solid = conical sutface area of cone + Area of circle + Cylindrical area of cylinder.
Conical sutface area of cone =πrr2+h2=204.203 cm2
Conical of cirle = πr2=78.54cm2
Cylindrical area of cylinder = 2πrh
=376.8cm2
Total surface area 659.543cm2
Answer By Abhishek Aade
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