Question

BRAINLIEST !!! BRAINLIEST !!​

Answer 1

Answer:

A trapezium PBCQ with its parallel sides QC and PB in the ratio of 7:5 is cut off from a rectangle ABCD if the area of trapezium is4/7 part of area of rectangle find the length of QC and PB

Area of Rectangle =  AB  * BC

Area of Trapezium = (1/2) ( PB + QC)  * BC

Let say QC = 7x  then PB = 5x

=> Area of Trapezium = (1/2)(5x + 7x) * BC

=> Area of Trapezium = 6x * BC

Area of Trapezium  = (4/7) Area of Rectangle

=> 6x * BC = (4/7)  *  AB * BC

=> x = 2AB/21

QC = 7x =  2AB/3

PB = 5x = 10AB/21

if we say AB = 21 cm as per attached fig

then QC = 14cm   & PB  = 10 cm

Step-by-step explanation:

Answer 2

Area of Rectangle =  AB  * BC

Area of Trapezium = (1/2) ( PB + QC)  * BC

7x  then PB = 5x

Area of Trapezium = (1/2)(5x + 7x) * BC

Area of Trapezium = 6x * BC

Area of Trapezium  = (4/7) Area of Rectangle

6x * BC = (4/7)  *  AB * BC

x = 2AB/21

14cm   & PB  = 10 cm