Math, asked by spacelover123, 10 months ago

BRAINLIEST for correct answer

Answer 2 questions correctly and write an explanation to get the chance of winning brainliest

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Answers

Answered by Mankuthemonkey01
71

1) 28 stamps were divided in some ratio between Sachin and Farooq. Which of these could be that ratio?

a) 2:8

b) 2:5

c) 2:3

d) 1:7

\rule{50}2

Answer

b) 2:5

Explanation

Let, the ratio of stamps distributed to Sachin and Farooq be x : y.

Then, Sachin gets

x/(x + y) × 28 stamps

and, Farooq gets

y/(x + y) × 28 stamps

(Ratio/(sum of ratios) × total = actual number)

Now, we know that a stamp would be distributed as a whole. Hence, in order to get whole number, from 28x/(x + y) or, 28y/(x + y), 28 should be divisible by (x + y).

Hence, the sum of ratios shod be factor of 28.

In the given options, only second option has sum of ratio (7) as a factor of 28. Hence, second option is the right answer.

\rule{100}2

2) If (A $ B) = (2A + B)/(A - 2B) then what will be the value of (6 $ 2)?

a) 1

b) 2

c) 3

d) 7

\rule{50}2

Answer

d) 7

Explanation

Put 6 as A and 2 as B

Then,

(6 $ 2) = (2 × 6 + 2)/(6 - 2 × 2)

→ (6 $ 2) = (12 + 2)/2

→ (6 $ 2) = 14/2

→ (6 $ 2) = 7

Answered by Sharad001
141

Question (1) :-

28 stamps were divided in some ratio between Sachin and Farooq .which of these could be that ratio .

a) 2 : 8

b) 2:5

c) 2:3

d) 1:7

Answer :-

→ (b) 2:5

Explanation :-

According to the question,

→ 28 stamps divided in some ratio between them .

Let, the ratio of stamps is p:q

Hence ,

Stamps got by Sachin ( x) is -

 \leadsto \sf \: x =  \frac{p}{p + q}  \times 28  =  \frac{28p}{p + q}  \\

And , stamps got by Farooq (y) is -

 \leadsto \sf \: y =  \frac{q}{p + q}  \times 28 =  \frac{28q}{p + q}  \\

Hence ratio of both x: y is -

 \to \sf x : y =  \frac{ \frac{28p}{p + q} }{ \frac{28q}{p + q} }  \\   \\ \to \sf \: x : y =  \frac{p}{q}

therefore the sum of ratios should be factor of 28 ,

• option (a) is of sum {2+8= 10} ( not a factor of 28 )

• option (b) is of sum {2+5 = 7} ( a factor of 28)

• option (c) is of sum {2+3 = 5} ( not a factor of 28 )

• option (d) is too not a factor of 28

Hence option (b) is correct .

\________|________/

Question (2) :-

If ( A $ B ) = ( 2A + B ) / (A - 2 B )

then find the value of (6 $ 2)

Answer :-

→ (6 $ 2 ) = 7 { option d is correct }

Explanation :-

Only exchanging of digits

A will replace by 6 and B will replace by 2 then -

→ (6 $ 2 ) = ( 12 + 2) / ( 6 - 2×2)

→ (6 $ 2 ) = (14)/2

→ (6 $ 2 ) = 7

\________|________/


Anonymous: Solve 2nd question too
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