Brainliest kaun hai...??
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Given, P = 2 kW
2 kW = 2 x 1000 W
2 kW = 2 x 1000 W = 2000 W
2 kW = 2 x 1000 W = 2000 W
Voltage(V)= 220 V
We know P= VI
Therefore the current drawn(I)=
= 9 A
The current drawn by the electric oven is 9 Amperes which is high as compared to the fuse in the electric circuit which is of only 5 Amperes as a result the fuse will blow off cutting of the power supply when the electric oven will operate...
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