Brainliest List..I'll add u plz help
9th grade Q...
Factorie:
x6-y6
Those two 6 are its powers n my problem is that it has no middle term to split...
Answers
Answered by
61
x^6 = (x³)²
and, y^6 = (y³)²
so, x^6 - y^6
= (x³)² - (y³)²
Now using, a² - b² = (a + b)(a - b)
assuming a = x³ and b = y³
(x³)² - (y³)²
= (x³ + y³)(x³ - y³)
now using the identity,
a³ - b³ = (a - b)(a² + b² + ab)
and a³ + b³ = (a + b)(a² + b² - ab)
we get,
(x³ + y³)(x³ - y³)
= (x + y)(x² + y²- xy)(x - y)(x² + y² + xy)
Hope it helps dear friend ☺️✌️✌️
and, y^6 = (y³)²
so, x^6 - y^6
= (x³)² - (y³)²
Now using, a² - b² = (a + b)(a - b)
assuming a = x³ and b = y³
(x³)² - (y³)²
= (x³ + y³)(x³ - y³)
now using the identity,
a³ - b³ = (a - b)(a² + b² + ab)
and a³ + b³ = (a + b)(a² + b² - ab)
we get,
(x³ + y³)(x³ - y³)
= (x + y)(x² + y²- xy)(x - y)(x² + y² + xy)
Hope it helps dear friend ☺️✌️✌️
Mankuthemonkey01:
Thanks @yukta
Answered by
60
Given Equation is x^6 - y^6
It can be written as,
= > (x^3)^2 - (y^3)^2
We know that a^2 - b^2 = (a + b)(a - b)
= > (x^3 + y^3)(x^3 - y^3)
We know, a^3 + b^3 = (a + b)(a^2 - ab + b^2), a^3 - b^3 = (a - b)(a^2 + ab + b^2)
= > (x + y)(x^2 - xy + y^2)(x^3 - y^3)
= > (x + y)(x^2 - xy + y^2)(x - y)(x^2 + xy + y^2)
= > (x + y)(x - y)(x^2 - xy + y^2)(x^2 + xy + y^2).
Hope this helps!
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