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Physics :-
A cyclist moving with a uniform speed of 36km /h . If the radius of each wheel is 0.25 m, calculate the angular speed of wheels.
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Solution :-
We will be using this in order to Solve :-
• v = 2πr/T
• and Omega = 2π/T
Here
• Omega = angular velocity of the particle
• v = linear velocity of particle / velocity
• r = radius of particle
Now we have
r = 0.25 m
v = 36 km/h or
= 36 × 5/18
= 10 m/s
Now by putting the value :-
v = 2πr/T
→10 m/s = 2π(0.25)/T
→10 /(0.25) = 2π/T
→10 × 100/25 = 2π/T
→40 = 2π/T
Now as
Omega = 2π/T
→ Omega = 40
So angular velocity = 40 radians /sec
Anonymous:
Thanks!!
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