Math, asked by ronakgaur200, 10 months ago

Brainlist ? Urgent need of solution Please..
Q-There are four positive consecutive even numbers and three positive consecutive odd numbers. the smallest odd number is 7 less than the greatest Even Numbers. the average of the square of the four consecutive even number is 29 less than the sum of the squares of the three consecutive odd numbers. find the greatest even number ? 1)8 2)10 3)12 4)14

Answers

Answered by Anonymous
2

Answer:

the answer is option 2). 10

Attachments:
Answered by amitnrw
1

Greatest Even number = 10

Step-by-step explanation:

Let say greatest Even number = n

Then other even numbers

n-2 , n - 4 , n - 6

4 Consecutive even numbers

n-6  , n - 4 , n - 2 , n

the smallest odd number is 7 less than the greatest Even

=> n - 7 is smallest odd number

n-7 , n - 5 , n - 3 are the consecutive odd numbers

average of the square of the four consecutive even number

=( (n-6)² + (n-4)² + (n - 2)² + n²)/4

= ( n² + 36 - 12n + n² + 16 - 8n + n² + 4 - 4n + n²)/4

= (4n² + 56 - 24n)/4

= n² - 6n + 14

sum of the squares of the three consecutive odd numbers

= (n - 7)² + (n - 5)² + (n - 3)²

= n² + 49 - 14n + n² + 25 - 10n + n² +9  - 6n

= 3n² - 30n + 83

n² - 6n + 14 =  3n² - 30n + 83  - 29

=> 2n² - 24n + 40= 0

=>  n² - 12n + 20 = 0

=> n² - 2n - 10n + 20 = 0

=> n(n - 2) - 10(n - 2)  = 0

=> (n - 10)(n - 2) = 0

=> n = 10

as n = 2 will lead into -ve integers for

Greatest Even number = 10

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