Physics, asked by taannaa, 1 year ago

Brainly benefactors.... plz answer
A particle is projected with velocity 40m/sec at an angle of theta. after 2 sec, it crosses a vertical pole of height 20.4 m. find its angle of projection and range.

Answers

Answered by AionAbhishek
4
see the pic attached
here we can use formula of t maximum beacuse at the particular height of the tower its reach is max time is 2s is given .
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taannaa: thank u.......
Answered by arunpatodi18
0

Explanation:

20.4

tha usino

Xx10= sino

I sind

Sin 30

9 = 30"

R = (40) X Sin 60°

R = 1800 x

240

pls mark brainliest

80 km

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