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Four years ago, Alex was twice as old as Jake. Four years from now, Jake will be 3/4 of Alex's age. How old is Alex?
Answers
Answered by
28
Let Jake Age 4 years Ago=x years
Then Alex Age=2x years.
Present Age of Jake=(x+4) years
Present Age of Alex=(2x+4) years.
4 years from Now.
Jake age=(x+4+4)=x+8 years
Alex Age=(2x+4+4)=2x+8 years
Jake is Age is of Alex Age.
A/Q
Alex Present Age=(2x+4)
=2×4+4
=12
Then Alex Age=2x years.
Present Age of Jake=(x+4) years
Present Age of Alex=(2x+4) years.
4 years from Now.
Jake age=(x+4+4)=x+8 years
Alex Age=(2x+4+4)=2x+8 years
Jake is Age is of Alex Age.
A/Q
Alex Present Age=(2x+4)
=2×4+4
=12
Anonymous:
Four years from now the age of Jake was 3/4 th of Alex , not their present age .. the equation will be x+8 = 3/4( 2 x + 8 ) . x = 4 , alex = 2 x + 4 = 2(4) + 4 = 12 .
Answered by
19
Let the present age of Alex be x .
Four years ago , the age of Alex would be x - 4 .
Four years ago , Alex is twice than Jake .
So the age of Alex is twice than Jake .
Let Jake's age be y .
x - 4 = 2 y
⇒ ( x - 4 )/2 = y
∴ the age of Jake 4 years ago was ( x - 4 )/2 and that of Alex was x - 4 .
Now 4 years from now :
we have to add 8 both sides because 4 years from the past + 4 years in future .
Jake 4 years after will become ( x - 4 )/2 + 8 and Alex becomes x + 4 .
Given that Jake is 3/4 th of Alex's age we can now calculate the value of x :
The present age of Alex is 12 years .
EXTRA INFO :-
The present age of Jake = 8
4 years ago it was ( 12 - 4 )/2 = 8/2 = 4 .
Currently it is 4 + 4 = 8 .
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