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A stone is thrown vertically upwards with the velocity of 10m/s Calculate the time taken by it to reach the highest point also . Find the height attained​

Answer 1

Here its given that

Initial velocity (u) = 10m/s

Final velocity (v) = 0m/s

$\sf \: Acceleration \: due \: to \: gravity \: = {9.8m/s}^{2}$

We have to find

Time

Height

Let's start

Using

$\sf \: v = u + gt$

here

V = Final velocity

u= Initial velocity

g = Acceleration due to gravity

t= time

Let's put values

$\sf \: 0 = 10 + ( { - 9.8} \times t)$

Here Acceleration due to gravity is negative as stone is thrown vertically upwards

$\sf \: - 10 = - 9.8t$

$\sf \: 10 = 9.8t \: \: (cancel)$

$\sf \: \frac{10}{9.8} = t$

$\sf \: or \: t \: = \frac{10}{9.8}$

$\sf \: or \: t = 1.0204 \: seconds$

Now to find height we will use

$\sf \: h = ut + \frac{1}{2} g {t}^{2}$

Putting values

$\sf \: h = 10 \times 1.0204 + \frac{1}{2} \times - 9.8 \times ( {1.0204}^{2} )$

$\sf \: h = 10.204 - \frac{1}{2} \times ( 10.2039)$

$\sf \: h = 10.204 - 5.10195$

$\sf \: h = 5.10205m$

The formula used

$\sf \: v = u + gt$

$\sf \: h = ut + \frac{1}{2} g {t}^{2}$

Answer 2

Explanation:

A stone is thrown vertically upwards with the velocity of 10m/s Calculate the time taken by it to reach the highest point also . Find the height attained