Question

BRAINLY.IN
how many minimum number of square of side 15 cm are needed to cover rectangular floor of dimension 5.25 m and 5.10 m completely

Answer 1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\boxed { \huge \mathcal\red{ solution}}}}$

$\huge \star$ For the Rectangular Floor:-

length(l)=5.25 m=525 cm

breadth (b)=5.10 m=510 cm

$\therefore$Area=(l×b)=(525×510) cm²

$\huge \star$ For the square:-

side(d)=15 cm

$\therefore$Area=d²=15² cm²

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$\therefore$No. Of Tiles:-

$\implies No. \:Of \:Tiles=\frac{525\times510}{15\times15}\:pcs\\ \implies \boxed{\bf\red{No. Of\: Tiles=1190 \:pcs}}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

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