Question

brainly legends please
$\: hi \: The \: shape \: of \: solid \: iron \: rod \: is \: a \: \: cylindrical. Its \: height \: is \: 11 cm. and \: base \: diameter \: is \: 7 cm \: . Then \: find \: the \: total \: volume \: of \: 50 \: such \: rods?\ \textless \ br /\ \textgreater$

Answer 1

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$\underline{SOLUTION}$ ➡

$given \\ \\ for \: \: the \: \: cylinderical \: \: shape \: \: rod \\ \\ height \: \: h = 11 \: \: cm \\ \\ diameter \: d = 7 \: \: cm \\ \\ so \: \: radius \: \: r = \frac{d}{2} \: = \frac{7}{2} \: \: cm$




$volumn \: \: of \: \:the \: \: rod = \pi \: r {}^{2} h \\ \\ = ( \frac{22}{7} \times ( \frac{7}{2} ) {}^{2} \times 11) \: \: cm {}^{3} \\ \\ = (\frac{22}{7} \times \frac{49}{4} \times 11) \: \: \: cm {}^{3} \\ \\ = 847 \: \: cm {}^{3}$



$now \\ \\ volumn \: \: of \: \: 1\: \: rod = \: 847 \: \:c m {}^{3} \\ \\ so \\ \\ volumn \: \: of \: \: such \: \: 50 \: \: rods =( 847 \times 50) \: \: cm {}^{3} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 42350 \: \: cm {}^{3}$



$\underline{ANSWER}$ ➡

$volumn \: \: of \: \: such \: \: 50 \: \: rods \: = 42350 \: \: cm{}^{3}$



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