Question

❤️ BRAINLY MATES❤️

GOT A DOUBT IN THE FOLLOWING QUESTION:-⤵️

✨An electric heater of resistance 8 ohm draws 15A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater. ✨

The answer is 1800W, shouldn't we use the formula H = I^Rt to solve it??

I m hella tired of thinking about this =_="

Answer 1

R=8ohm
I=15A
time =2 hours
P=I²R
15²×8
=225×8
=1800
We need to find the rate at which heat is released not the heat which in released.. ..
So power is rate of consumption of energy so we used formula of power = I²R

Answer 2

heya deary...❤️❤️

here is ur answer☺️☺️☺️


hope it helps u❣️❣️