#☆Brainly members♡♡♡ pls help me♡♡♡
Make it on page........
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>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
HEAT OBTAINED = HEAT REQUIRED TO RAISE THE TEMPERATURE OF WATER
HEAT PROVIDED TO WATER = Heat capacity × mass × ∆Temperature
4200 J × 1 kg × 2.5
= 10500 J
HEAT OBTAINED BY KEROSENE = 10500 J
MASS = 0.05 g
HEAT CAPACITY { calorific value } = Energy / mass { if ∆t = 1 }
HEAT CAPACITY ( ∆t = 1 ) = 10500/0.05
= 200000 J/g
OR
= 200 J/kg
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 200 J/kg
>>>>>>>>>>>>>>>>>>>>>>>>>>>
HOPE IT HELPS :):):):):):):):):):):):):)
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
HEAT OBTAINED = HEAT REQUIRED TO RAISE THE TEMPERATURE OF WATER
HEAT PROVIDED TO WATER = Heat capacity × mass × ∆Temperature
4200 J × 1 kg × 2.5
= 10500 J
HEAT OBTAINED BY KEROSENE = 10500 J
MASS = 0.05 g
HEAT CAPACITY { calorific value } = Energy / mass { if ∆t = 1 }
HEAT CAPACITY ( ∆t = 1 ) = 10500/0.05
= 200000 J/g
OR
= 200 J/kg
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 200 J/kg
>>>>>>>>>>>>>>>>>>>>>>>>>>>
HOPE IT HELPS :):):):):):):):):):):):):)
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