Question

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Answer 1

Answer:

→ Hey Mate ,

→ Given Question : In the figure ,arc SBT is one quarter of a circle with     centre R and radius 6 . If the length plus  the  width of rectangle ABCR is 8 , then the perimeter of the shaded region is

Step-by-step explanation:

→ Solution :

→ To Solve : SA + AC + CT + Arc  SBT

→ Arc  SBT  = ( 2πr) / 4

→ 2π( 6 ) / 4 = 3π

→ SA + AC + CT

→ ( SR - AR) + AC + ( RT - RC )

→ =  SR + AC + RT - ( AR + RC)

→  SR  = RT  = 6 ( radius of  circle )

→ AC = AC  = 6 ( radius of circle )

→ 6+ 6 + 6 - 8  = 10

→ SA + AC + CT + Arc SBT  = 10 + 3π

→ Answer =  10 + 3 π

thank you

Answer 2

$\red{ANSWER}$

We know that :

• The length of the curve is one-fourth the circumference of the circle, and r= 6:

$\green{Length \: of \: curve =} \\ \\ \blue{ \frac{2\pi}{4} } = \pink{ \frac{12\pi}{4}} =3 \pi$

Explanation

• Now see the details answer in above attachment

• Refer the attachment

Final Answer

$\green{10 + 3 π}$