Question

Brainly moderators
Brainly stars
Brainly best users

high quality answer needed


question: If x=1-root(2),then find the value of (x-1/x)whole square

give clear explanation for class 9

answer only if you know or else you ll be reported​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

$to \: find = \\ \\ (x - \frac{1}{x} \: ) {}^{2} \\ \\ given = \\ x = 1 - \sqrt{2} \\ \\ thus \: then \\ \\( x - \frac{1}{x} \: ) {}^{2} = (1 - \sqrt{2} \: - \: \frac{1}{1 - \sqrt{2} } \: ) {}^{2} \\ \\ = \frac{( 1 - \sqrt{2} ) {}^{2} - 1}{1 - \sqrt{2} } \\ \\ = \frac{1 + 2 - 2 \sqrt{2} - 1}{1 - \sqrt{2} } \\ \\ = \frac{2 - 2 \sqrt{2} }{1 - \sqrt{2} } \\ \\ = \frac{2(1 - \sqrt{2} )}{1 - \sqrt{2} } \\ \\ = 2$

Answer 2

Step-by-step explanation:

$\begin{gathered}to \: find = \\ \\ (x - \frac{1}{x} \: ) {}^{2} \\ \\ given = \\ x = 1 - \sqrt{2} \\ \\ thus \: then \\ \\( x - \frac{1}{x} \: ) {}^{2} = (1 - \sqrt{2} \: - \: \frac{1}{1 - \sqrt{2} } \: ) {}^{2} \\ \\ = \frac{( 1 - \sqrt{2} ) {}^{2} - 1}{1 - \sqrt{2} } \\ \\ = \frac{1 + 2 - 2 \sqrt{2} - 1}{1 - \sqrt{2} } \\ \\ = \frac{2 - 2 \sqrt{2} }{1 - \sqrt{2} } \\ \\ = \frac{2(1 - \sqrt{2} )}{1 - \sqrt{2} } \\ \\ = 2\end{gathered}$