Physics, asked by NeetHeIper, 11 days ago

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Asked Question :-


A bus moves from rest to a speed of 900m/s in 25seconds. What is the magnitude of bus acceleration?

Answers

Answered by BrainlyEmpire
314

\red\bigstarGiven :

:\mapsto Initial velocity of Bus (u) = 0

:\mapsto Final velocity of Bus (v) = 900m/s

:\mapsto Time taken by Bus (T) = 25sec

\;\;

\pink\bigstarNeed to FinD :

:\implies Magnitude of Bus acceleration?

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\green\bigstarFormula Used Here :

  • :\mapstov = u + at

\red\dagWhere :

  • » v = Final velocity
  • » u = Initial velocity
  • » a = acceleration
  • » t = Time taken

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\purple\malteseUnderstanding the concept :

➣ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of Bus !

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\red\dagPutting value in formula :

\qquad\twoheadrightarrowv = u + at

\qquad\twoheadrightarrow900m/s = 0 + a × 25s

\qquad\twoheadrightarrow900= 0 + 25a

\qquad\twoheadrightarrow900= 25a

\qquad\twoheadrightarrowa = 36 m/s²

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\orange\maltese Therefore :

:\red\longmapsto Acceleration of Bus is 36 m/s²

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\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \:\bf\:More\:to\:know\:\bigstar}}}} \\ \\

\;\;\blue\bigstarSome important formulas :

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\;\;\;\;\;\;\;\;\orange{\boxed{ \begin{array}{cc}    {\pmb{\dag{\red{\bf{ \quad \: v = u + gt \quad}}}}}  \\  \\  \frak{\pmb{\dag{\pink{\bf{ \quad \:  h= ut}}}}} +  \cfrac{\pmb{\sf{ 1}}}{\pmb{\sf{ 2}}}\pmb{\sf{ g}}{\pmb{\sf{ t}}}^{\pmb{\sf{ 2}}} \quad \: \\ \\ \pmb{\dag{\purple{\bf{ \quad \:  {v}^{2} -  {u}^{2}  = 2gh \quad \:}}}}\end{array}}}

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Answered by AdvancedQuestioner
2

Explanation:

★ Given :

↦ Initial velocity of Bus (u) = 0

↦ Final velocity of Bus (v) = 900m/s

↦ Time taken by Bus (T) = 25sec

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