Question

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Show graphically that the system of equations 2x + 3y = 10,4x +6y 12 has no solution.​

Answer 1

Given, 2x + 3y = 6……. (i) 4x + 6y = 12……. (ii) For equation (i), ⇒ y = ( 6 – 2 x ) 3 (6–2x)3 When x = 0, we have y = ( 6 – 2 ( 0 ) ) 3 (6–2(0))3= 2 When x = 3, we have y = ( 6 – 2 ( 3 ) ) 3 (6–2(3))3 = 0 Thus we have the following table giving points on the line 2x + 3y = 6 x 0 3 y 2 0 For equation (ii), We solve for y: ⇒ y = ( 12 – 4 x ) 6 (12–4x)6 So, when x = 0 y = ( 12 – 4 ( 0 ) ) 6 (12–4(0))6 = 2 And, when x = 3 ⇒ y = ( 12 – 4 ( 3 ) ) 6 (12–4(3))6 = 0 Thus we have the following table giving points on the line 4x + 6y = 12. x 0 3 y 2 0 Graph of the equations (i) and (ii) is as below: Thus, the graphs of the two equations are coincidence

Answer 2

Answer:

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