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The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonals of the rhombus is 22 cm, find the length of the other diagonal.
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Answered by
25
Answer:
Area of Rhombus ABCD =
1/2 × diagonal1 × diagonal2
= 1/2 × 22 × d ………….(1)
Area of triangle PQR
= 1/2 × Base × corresponding altitude
= 1/2 × 24.8 × 16.5 ………….(2)
Given that these 2 areas ( 1) & (2) are equal
=> 1/2 × 22 × d = 1/2 * 24.8 × 16.5
=> d = (24.8 × 16.5) /22
=> d = 186/10
=> diagonal = 18.6 cm
Answered by
1
Answer:
density, of a substance is its mass per unit volume. The symbol most often used for density is ρ, although the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume: {\displaystyle \rho ={\frac {m}{V}}} where ρ is the density, m is the mass, and V is the volume.
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