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Five Years Hence, The Age Of Jacob Will Be Three Times That Of His Son. Five Year Ago, Jacob’s Age Was Seven Times That Of His Son. What Are Their Present Ages?​

Answer 1

The answer is in the above attachment :)

Answer 2

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Let present age of Jacob = x years.

Present age of Jacob's son = y years.

Five years hence

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎Jacob's Age = x+5

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎Jacob son's Age = y+5

Age of Jacob will be three times of his son.

$x + 5 = 3(y + 5) \\ x + 5 = 3y + 15 \\ x - 3y = 15 - y \\ x - 3y = 10..(1)$

Also,

Five years ago,

Jacob's age = X-5

Jacob son's age = y - 5

Age of Jacob was seven times of his son.

$x - 5 = 7(y - 5) \\ x - 5 = 7y - 7(5) \\ \\ (3y + 10) - 7y = - 30 \\ 3y + 10 - 7y = - 30 \\ - 4y = - 30 - 10 \\ - 4y = - 40 \\ y= \frac{ - 40}{ - 4} \\ y = 10$

Putting y = 10 in . . . . . . . . . (1)

$x - 3y = 10 \\ x = 3(10) = 10 \\ x - 30 = 10 \\ x = 10 + 30 \\ x = 40$

So x = 40, y = 10

Thus,

Present age of Jacob = x = 40 years

Present age of Jacob's son = y = 10 years

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Hope it helps you:)

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