Question

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Answer 1

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In given figure parallelogram PORS, PR and QS diagonal intersect at O.

We know that the diagonal intersect at right angle each other

The line LM is parallel to PS

Then diagonal of parallelogram divided in equal area of triangles

Then area ∆POQ= area of ∆POS= area of ∆QOR= area of ∆SOR

$\sf \: OR \: Area \: of \: ∆POS \: + \: area \: of \: ∆QOR \: = \frac{1}{2} \: area \: of \: parallelogram$

Then area of ∆POS + area of ∆QOR = area of ∆POQ + area ∆ SOR

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