Question

Brainly Stars ☆
Advanced Moderators ♤
And other best users ♡
Solve this Need help please​

Answer 1

$\: \: \: \huge\color {pink}\boxed{\colorbox{black} {✯Answer}}$

We know that, diagonals in a rhombus bisect each other perpendicularly. Let O is the intersecting point of diagonals AC and BD.

$\sf \: OA = \frac{AC}{2} = \frac{16}{2 } = 8cm$

$\sf \: OB = \frac{BD}{2} = \frac{12}{2} = 6cm$

$\sf \: now \: in \: \triangle \: AOB \: ,\angle \: AOB = 90 \degree$

⇒ (AB)² = (OA)² + (OB)² [ by Pythagoras theorem]

⇒ (AB)² = (8)² + (6)²

⇒ (AB)² = 64 +36

⇒ (AB)³ = 100

⇒ AB = 10 cm

⇒We know that, all sides of rhombus are equal.

⇒The length of each side of rhombus is 10 cm