Question

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Answer 1

$\: \: \: \: \huge\color {pink}\boxed{\colorbox{black} {✯Answer}}$

$\sf \angle \: XBY \cong \angle \: ABC \: \: \: [vertically \: opposite \: angle]$

$\sf \angle \: XBY \: = \: 90 \degree$

$\sf \: now \: has \: the \: \triangle \: BXY \: is \: isoscles$

$\sf \: so \: \angle \: x = \angle \: y$

$\sf \: now \: \angle \: XBY \: + \: \angle \: x \: + \angle \: y \: = 180 \degree$

$\sf \: 90 \degree \: + \angle \: x \: + \angle \: x \: = \: 180 \degree$

$\sf \: 2 \: \angle \: x \: = \: 90 \degree$

$\sf \angle \: x \: = \: 45 \degree$

$\sf \: Ans \: ☞ \angle \: x \: = \: 45 \degree \: \angle \: y \: = \: 45°$