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x + y = 3 ( z + u)
x+ y = 4 ( y + u)
x+ u = 5 ( y+ z)
what is the minimum possible value of x if x, y, z and u are all positive integers?
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Answer:
a +b use formula and Answers it
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Answer:
Hey Mate ,
→ Given Question : x + y = 3 ( z + u)
→ x+ y = 4 ( y + u)
→ x+ u = 5 ( y+ z)
what is the minimum possible value of x if x, y, z and u are all positive integers?
Step-by-step explanation:
→ Solution :
→ x + y - 3z - 3 u = 0 ( ∵ equation 1 )
→ x - 4y + z - u = 0 ( ∵ equation 2 )
→ x - 5y - 5z + u = 0 ( ∵ equation 3 )
→ ( 1 ) + 3 ( 3 ) : 4x - 14 y - 18z = 0 ( ∵ equation 4 )
→ ( 2 ) + 4 ( 3 ) 5x - 24y - 19 z = 0 ( ∵ equation 5 )
→ 12 ( 4 ) - 7 ( 5 ) : 13x - 8 3 z = 0
→ 13x = 8 3z
→ x = 8 3
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→ Thank you
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