Question

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Solve the question given in the attachment.

#Neet
#Class 12th
#Electrostatics​

Answer 1

Net Potential at point A will be :

$V_{A} = \dfrac{k( 2q)}{d} + \dfrac{k( - q)}{2d}$

$\implies V_{A} = \dfrac{2kq}{d} - \dfrac{kq}{2d}$

$\implies V_{A} = \dfrac{kq}{d} \bigg( \dfrac{4 - 1}{2} \bigg)$

$\implies V_{A} = \dfrac{kq}{d} \bigg( \dfrac{3}{2} \bigg)$

$\implies V_{A} = \dfrac{3kq}{2d}$

• For the second question, the points for which potential difference has to be calculated is not given in question. So, the data is incomplete.

FINAL ANSWER WILL BE:

• OPTION D) : NONE