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$\Large{\underline{\underline{\mathfrak{ \bigstar \: Question \: \bigstar }}}}$
In a $\triangle\sf{ABC}$, $\angle\sf{B = 35°}$ and $\angle\sf{C = 55°}$. Write which of the following is true:

(i) AC² = AB² + BC²
(ii) AB² = BC² + AC²
(iii) BC² = AB² + AC²
​

Answer 1

Answer᭄

(iii)BC² = AB² + AC²

Step-by-step explanation:

$\large\underline{Given:-}$

• ∠B=35°
• ∠C=55°

$\large\underline{Solution:-}$

35+55+∠A=180°

( Linear pair )

∠A=180°-90°

∠A=90°

❥It means ∆ABC is a right angled triangle

❥By Pythagoras theorem

that is,

a²=b²+c²

where,

• a=hypotenuse
• b=perpendicular
• c=base

here,

• a=BC
• b=AC
• c=AB

So,

BC²=AC²+AB²

is the correct answer

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Answer 2

Given :

$\angle\sf{B = 35°}$ $\angle\sf{C = 55°}$

To Find :

$\angle\sf{A = ?}$

Solution :

Let angle A be x

$\angle\sf{B }+ \angle\sf{C}+ \angle\sf{A}$ = 180(Angle sum property of triangle

Let A be x

35 + 55 + x = 180

90 + x = 180

x = 180 - 90

x = 90

So, option (iii) is correct

BC² = AB² + AC²