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Given that, diameter(d) of cylinder is 1.4 m and length(h) is 8 m.
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
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Answer:
!!
Step-by-step explanation:
Total surface area of cylinder = 2 pi r( r+h)
According to the question
Total surface area of given cylinder 2 ❌ 22/7❌ 0.7 ( 0.7 + 8) = 4.4❌ 8.7= 42.68sq.m
Cost of painting cylinder at rate of 20/sq.m= 42.68❌ 20 = Rs. 853.6
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