Question

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$\red{ \underline{ \sf \red{ Question:-}}}$

A number 'x' is selected from the numbers 1, 2, 3 and then a second 'y' is randomly selected from the numbers 1,4,9 . What is the probability that the product 'xy' of the two numbers will be less than 9?
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Answer 1

Answer:—

$= > \dfrac{5}{9}$

Step-by-step explanation:

Given:—

A number x is selected from the numbers 1,2,3 and then a second number y is randomly selected from the numbers 1,4,9.

Total number of outcomes for product of two numbers selected from x any:—

→ 3×3=9

The outcomes for which the product xy of the two numbers selected will be less than 9 : 1×1 , 1×4, 2×1, 2×4, 3×1

Hence,

The number of desired outcomes = 5

Then,

The probability that the product xy of the two numbers selected will be less than 9 :—

$\begin{gathered}\dfrac{\text{Desired outcome}}{\text{Total outcomes}}\\ \: \: \\ =\dfrac{5}{9}\end{gathered}$

Honestly said copied from Go_ogle

Answer 2

Answer:

Total number of ways the two numbers ca be selected is :

• (1,1)
• (1,4)
• (1,9)
• (2,1)
• (2,4)
• (2,9)
• (3,1)
• (3,4)
• (3,9)

So the total number of outcomes is 9

ATQ, the product must not exceed more than 9

Hence,

Possible out comes are:

➳ (1,1)

➳ (1,4)

➳ (2,1)

➳ (2,4)

➳ (3,1)

So the possible number of outcomes is 5

So the probably will be given by,

$\sf \implies{ \displaystyle\sf Probability = \dfrac{Possible \ outcomes}{Total \ no \ of \ outcomes}}$

◕ Possible Outcomes = 5

◕ Total outcomes = 9

$\sf \implies\displaystyle\sf \pink{Probability = \dfrac{5}{9}}$

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