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A man goes 20 m due east and the 15 m due South.Find the distance between his starting point and ending point.
Answers
Answered by
2
HI MATE !
WE CAN FIND THE ANSWER THROUGH PYTHAGORUS THEORAM !
the distance point from starting point to ending point = square root of {(20)^2 + (15)^2 }
= square root of 625
= 25
Therefore the distance between the starting point to ending point is 25m
HOPE IT HELPS MATE!
WE CAN FIND THE ANSWER THROUGH PYTHAGORUS THEORAM !
the distance point from starting point to ending point = square root of {(20)^2 + (15)^2 }
= square root of 625
= 25
Therefore the distance between the starting point to ending point is 25m
HOPE IT HELPS MATE!
Answered by
1
hey friend your answer........
he goes 20m east and 15m south.
these directions are perpendicular to each other, so using Pythagoras theorem.
H²=20²+15²
H²=400+225
H²=625
H=25
So the displacement is 25m.
he goes 20m east and 15m south.
these directions are perpendicular to each other, so using Pythagoras theorem.
H²=20²+15²
H²=400+225
H²=625
H=25
So the displacement is 25m.
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