Question

brainly wasiyon, Good Morning , Thori help chahiye ✌️​

Answer 1

Answer:

160

Explanation:

Let E be the effort applied on the smaller piston A and L be the load required on the larger piston B.  

Area of cross section of piston A=8 cm  ^2

Area of cross section of piston A=320cm^2

 (i) Pressure acting on piston A in the downward direction= Thrust/Area=E/8=4/8=0.5

∴Pressure acting on water = E/8=0.5 (according to Pascal's Law)

(ii) ∴ Pressure acting on piston B=E/8=0.5 (according to Pascal's Law)

(iii) Thrust acting on piston B in the upward direction =Pressure ×Area of B

=  (E×320 )/8

=160

Hope this helps you☺...................