Question

brakes applied to a car produce a uniform retardation of 0.5 metre per second square if the car was travelling with a velocity of 25 metre per second,what distance will it before coming to rest​

Answer 1

Explanation:

$\huge\bold\red{itzurqueen01}$

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Answer 2

Answer:

$\green{ \boxed{\bf \odot \: \: \: \: \: distance \: \: s = 625 \: m }}$

Explanation:

Given,

$\bf \odot \: \: initial \: velocity \: \: u = 25 \: m {s}^{ - 1} \\ \bf \odot \: \: final \: velocity \: \: v = 0 \: \: \: \pink{ \{ \: stopped \}} \\ \bf \odot \: \: retardation \: \: a \: = 0.5 \: \: m {s}^{ - 2} \\ \\ \green{ \bf \odot \: distance \: \: s = \: to \: find \: } \\ \\ \bf \: we \: know \: that \: \\ \\ \bf {v}^{2} = {u}^{2} - 2as \\ \bf \implies \: {0}^{2} = {(25)}^{2} - 2 \times 0.5 \times s \\ \bf \implies \:0 = 625 - 2 \times \frac{1}{2} \times s \\ \bf \implies \:s = 625 \: m \\ \\ \green{ \boxed{\bf \therefore\: \: \: \: distance \: \: s = 625 \: m }}$