brakes applied to a car produce a uniform retardation of 0.9 metre per second square if the car was travelling with a velocity of 27 metre per second what distance will it cover before coming to rest
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Answer:405 km
Explanation:
When the brakes are applied to a car produced a uniform retardation of 0.9 m/s2 if the car was travelling with velocity of 27 m/s:
v = 0 m/s
u = 27 m/s
a = -0.9 m/s2
To find out the distance travelled by the car, S before coming to rest we will use Newton's third equation of motion
v2 - u2 = 2aS, so 0^2-27^2=2*-0.9*S, so, 0-729=-1.8*S,or ,-729/-1.8=S,or, S=405 km.
Hope it helps mate
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